Question

A force of $6N$ is applied to 3 cubes with surface areas as shown. Match the cards with pressure.

• A. 3 Pa
• B. 2 Pa
• C. 6 Pa

Answer 1

We know that pressure acting on a body is given by, $P=\frac{F}{A}$

(i) For the first cube, $F=6N$ and surface area, $A=1m^2$
Therefore, the pressure acting on the first cube is, $P=\frac{F}{A}=\frac{6}{1}=6Pa$

(ii) For the second cube, $F=6N$ and surface area, $A=2m^2$
Pressure, $P=\frac{F}{A}=\frac{6}{2}=3Pa$

(iii) For the third cube, $F=6N$ and surface area, $A=3m^2$
Pressure, $P=\frac{F}{A}=\frac{6}{3}=2Pa$