Question

A force of 60 N acts on a body having an area of cross-section 5 cm². Calculate the pressure exerted by the body.

Answer 1

Step 1: Given data

Force acts on a body, $F=60N$

Area of cross-section, $A=5c{m}^2=5\times {10}^{-4}{m}^2$

Step 2: Formula used

Pressure is given as,

$Pressure\left(P\right)$$=$$\frac{F}{A}$

Putting all the values we have,

$P=$$\frac{F}{A}$ $=$ $\frac{60}{5\times {10}^{-4}}$

$=$ $120000$$N/m^2$

$=120000Pa$

Hence, the pressure exerted by the body is 120000 Pa.