A force of 60 N is pushing a body which moves it through a distance of 4 m on a horizontal surface. What is the work done, if the direction of force is at an angle of $60^{\circ}$ to the horizontal surface?

100 J

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120 J

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75 J

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120 N cm

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Solution

The correct option is B
120 J

Given:
Force $F = 60 N$ ,
Distance travelled in horizontal direction $S = 4 m$ ,
$θ = 60^{\circ}$
Since Work done $= F s c o s θ$
Substituting values
Work done $= 60 \times 4 \times c o s 60 = 120 J$

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Similar questions

A force of 60 N acts on a body which moves it through a distance of 4 m on a horizontal surface. What is the work done, if the direction of the force is at an angle of $60^{\circ}$ to the horizontal surface?

Q. (i) What happens to the work done when the displacement of a body is at right angle to the direction of force acting on it? Explain your answer.
(ii) A force of 50 N acts on a body and moves it a distance of 4 m on a horizontal surface. Calculate the work done if the direction of force is at an angle of 60° to the horizontal surface.

Q. (a) What happens to the work done when the dispacement of body is at right angles to the direction of force acting on it? Explain your answer.
(b) A force of 50 N acts on a body and moves it a distance of 4 m on horizontal surface. Calculate the work done if the direction of force is at an angle of 60° to the horizontal surface.

Q. A force of

15 N

displaces a box on a horizontal surface through a distance of

10 m

. Calculate the angle which the force makes with the direction of motion of the body, if work done is

75 J

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A force of 60 N is pushing a body which moves it through a distance of 4 m on a horizontal surface. What is the work done, if the direction of force is at an angle of 60∘ to the horizontal surface?

The correct option is B 120 J Given: Force F=60 N, Distance travelled in horizontal direction S=4 m, θ=60∘ Since Work done =Fs cosθ Substituting values Work done=60×4×cos 60=120 J

A force of 60 N is pushing a body which moves it through a distance of 4 m on a horizontal surface. What is the work done, if the direction of force is at an angle of $60^{\circ}$ to the horizontal surface?

The correct option is B
120 J

Given:
Force $F = 60 N$ ,
Distance travelled in horizontal direction $S = 4 m$ ,
$θ = 60^{\circ}$
Since Work done $= F s c o s θ$
Substituting values
Work done $= 60 \times 4 \times c o s 60 = 120 J$