Question

A force of $7kgwt$ is sufficient to pull a block of $10kgwt$ over a flat surface. What is the angle of friction?

Answer 1

The angle of friction is given as,

$\tan \theta =\frac{f}{R}$

$\tan \theta =\frac{7}{10}$

$\theta ={\tan }^{-1}\left(\frac{7}{10}\right)$

$\theta ={34.99}^{\circ }$

Thus, the angle of friction is ${34.99}^{\circ }$.