Question

A force of $8kgf$ raises a load of $4kg$ through $5m$ first and then the same force raises another load of $6kg$ through the same distance. So,

• A. It does greater work in raising the $6kg$ load
• B. It does less work in raising the $6kg$ load
• C. It does the same work in raising both the loads
• D. It cannot be said unless the time in which the work is done is given.

Answer 1

The correct option is C

It does the same work in raising both the loads

Step 1: Given data

Force, $F=8kgf$

First load, $m_1=4kg$

Second load, $m_2=6kg$

Distance traveled, $s=5m$

Step 2: Finding the work done

We know that work done,$W=F\times s$

where $F=\mathrm{force}\mathrm{applied};S=\mathrm{displacement}\mathrm{of}\mathrm{the}\mathrm{body}$

Since the force and displacement is equal in both cases, $F=8kgf,s=5m$

Thus,$W=8\times 5=40J$

Therefore, the amount of work done will be the same for both cases and the work done is independent of time.

Hence, option (c) is correct.