A force of $80 N$ acts on a rigid body at a distance of $1.5 m$ from the pivot point. Calculate the moment of force.

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Solution

Step 1: Given data
Force, $F = 80 N$
Distance, $D = 1.5 m$
Step 2: To find the moment of force
$M o m e n t o f f o r c e = F o r c e \times P e r p e n d i c u l a r d i s \tan c e$
$= 80 N \times 1.5 m$
$= 120 N$
Hence, the required moment of force is $120 N$ .

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A force of 80N acts on a rigid body at a distance of 1.5m from the pivot point. Calculate the moment of force.

Step 1: Given dataForce, F=80NDistance, D=1.5mStep 2: To find the moment of forceMomentofforce=Force×Perpendiculardistance =80N×1.5m=120NHence, the required moment of force is 120N.

A force of $80 N$ acts on a rigid body at a distance of $1.5 m$ from the pivot point. Calculate the moment of force.

Step 1: Given data
Force, $F = 80 N$
Distance, $D = 1.5 m$
Step 2: To find the moment of force
$M o m e n t o f f o r c e = F o r c e \times P e r p e n d i c u l a r d i s \tan c e$
$= 80 N \times 1.5 m$
$= 120 N$
Hence, the required moment of force is $120 N$ .