A force of 85 N is applied (parallel) to the incline surface on a block of weight 100 N resisting on the inclined plane μ=0.5 what will be the force?
Given that,
Force F=85N
Weight W=100N
μ=0.5
Now, the net force is
Fnet=F−umg
Fnet=85−0.5×100
Fnet=35N
Hence, the net force is 35 N