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Question

A force of 85 N is applied (parallel) to the incline surface on a block of weight 100 N resisting on the inclined plane μ=0.5 what will be the force?

A
20 N
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B
35 N
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C
40 N
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D
60 N
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Solution

The correct option is B 35 N

Given that,

Force F=85N

Weight W=100N

μ=0.5

Now, the net force is

Fnet=Fumg

Fnet=850.5×100

Fnet=35N

Hence, the net force is 35 N


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