Question

A force of $98N$ is just able to move a block of mass $20kg$ on a rough horizontal surface. Calculate the coefficient of friction and the angle of friction ($\gamma =9.8{ms}^{-2}$)

Answer 1

Here , maximum possible value of friction = $\mu mg$

= $98$ $N$

We get , coefficient of friction , $\mu$ = $0.5$.

Now , angle of friction = $ta{n}^{-1}\left(\mu \right)$

= $ta{n}^{-1}\left(0.5\right)$

= ${26.56}^{\circ }$