A force of magnitude 25 N acting on a body of mass 2 kg increases its kinetic energy from 100 J to 200 J. The displacement of the body during this interval is ___ m.

100

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Solution

The correct option is D 4
According to work-energy theorem, work done by the force is equal to the change in kinetic energy of the body.
Thus, change in kinetic energy is
$= {KE}_{f i n a l} - {KE}_{i n i t i a l} = 200 J - 100 J = 100 J = Work done$
We know that, $Work done = force \times displacement$
Therefore, $100 = 25 \times displacement$ .
So, the displacement = 4 m.

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