A force of magnitude $25 N$ acting on a body of mass $2 k g$ increases its kinetic energy from $100 J$ to $200 J$ . The displacement of the body during this interval is ___.

2 m

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4 m

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6 m

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8 m

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Solution

The correct option is B $4 m$
Given: Force $F = 25 N$ , mass $m = 2 k g$ , initial kinetic energy $= 100 J$ , final kinetic energy $= 200 J$
$∴$ change in kinetic energy $= 100 J$
According to work-energy theorem, work done by the force will be equal to the change in kinetic energy of the body. The change in kinetic energy is equal to 100 J and this is the work done on the body.
As we know that:
Work done = Force $\times$ displacement.
Therefore, 100 = 25 $\times$ displacement.
So, displacement = 4 m.

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A force of magnitude 25 N acting on a body of mass 2 kg increases its kinetic energy from 100 J to 200 J. The displacement of the body during this interval is ___.

A force of magnitude $25 N$ acting on a body of mass $2 k g$ increases its kinetic energy from $100 J$ to $200 J$ . The displacement of the body during this interval is ___.