A force of magnitude 35 N acting on a body of mass 4 kg increases its kinetic energy from 0 J to 210 J. The displacement of the body during this interval is___.

6 m

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5 m

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3 m

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Solution

The correct option is A
6 m

According to work-energy theorem, work done by the force would be equal to the change in kinetic energy of the body.

Change in kinetic energy = $210 - 0 = 210 J$

$\Rightarrow$ Work done = $210 J$

Work done = Force x Displacement.

$\Rightarrow$ 210 = 35 x Displacement.

$\Rightarrow$ Displacement = 6 m.

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A force of magnitude 35 N acting on a body of mass 4 kg increases its kinetic energy from 0 J to 210 J. The displacement of the body during this interval is___.

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A force of magnitude 35 N acting on a body of mass 4 kg increases its kinetic energy from 0 J to 210 J. The displacement of the body during this interval is___.

The correct option is A 6 m According to work-energy theorem, work done by the force would be equal to the change in kinetic energy of the body. Change in kinetic energy = 210−0=210J ⇒ Work done = 210J Work done = Force x Displacement. ⇒ 210 = 35 x Displacement. ⇒ Displacement = 6 m.