A force of magnitude $50 N$ acting on a body of mass $2 k g$ increases its kinetic energy from $100 J$ to $200 J$ . The displacement of the body during this interval is ___.

4 m

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5 m

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2 m

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3 m

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Solution

The correct option is C $2 m$
Given:
Force $F = 50 N$ ,
Mass $m = 2 k g$ ,
Initial kinetic energy $= 100 J$ ,
Final kinetic energy $= 200 J$
$∴$ change in kinetic energy $= 100 J$
According to work-energy theorem, work done by the force will be equal to the change in kinetic energy of the body.
Here, change in kinetic energy = $100 J$
As we know that:
Work done = Force $\times$ displacement.
Therefore, $100 J$ = $50 \times$ displacement.
So, displacement = $2 m$ .

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A force of magnitude $50 N$ acting on a body of mass $2 k g$ increases its kinetic energy from $100 J$ to $200 J$ . The displacement of the body during this interval is ___.