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Question

A force F=3^i+2^j4^k acts at the point (1,1,2). Find its torque about the point (2,1,3).

A
6^i7^j+^k
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B
2^i7^j2^k
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C
2^i+7^j2^k
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D
6^i+7^j+^k
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Solution

The correct option is B 2^i7^j2^k

Here, F=3^i+2^j4^k is acting at a point (1,1,2)
r=(12)^i+(1(1))^j+(23)^k=^i^k

Hence torque about point (2,1,3) :
τ=r×F
τ=(^i^k)×(3^i+2^j4^k)
τ=∣ ∣ ∣^i^j^k101324∣ ∣ ∣
τ=^i(2)^j(4+3)+^k(2)
τ=2^i7^j2^k

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