A force, →F=3^i+c^j+2^k acting on a particle causes a displacement →d=−4^i+2^j+3^k. If the work done is 6J, then the value of c is
A
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C 6 We know that work done by a force is given by, W=→F.→d=(3^i+c^j+2^k).(−4^i+2^j+3^k) =−12+2c+6=2c−6 From the question, 2c−6=6∴c=6