A force- F - 3- - c- - 2k- acting on a particle causes a displacement d- -4- - 2- - 3k- If the work done is 6 J- then the value of c is

We know that work done by a force is given by, nbsp; W = F . d = (3î + cĵ + 2k̂) . ( 4î + 2ĵ + 3k̂) = 12 + 2c + 6 = 2c 6 From the question, nbsp; 2c 6 ...

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Standard XII

Physics

Multiplication with Vectors

A force, F = ...

Question

A force, $\to F = 3^i + c^j + 2^k$ acting on a particle causes a displacement $\to d = - 4^i + 2^j + 3^k .$ If the work done is $6 J$ , then the value of $c$ is

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Solution

The correct option is C 6
We know that work done by a force is given by,
$W = \to F . \to d = (3^i + c^j + 2^k) . (- 4^i + 2^j + 3^k)$
$= - 12 + 2 c + 6 = 2 c - 6$
From the question,
$2 c - 6 = 6 ∴ c = 6$

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A force, →F=3^i+c^j+2^k acting on a particle causes a displacement →d=−4^i+2^j+3^k. If the work done is 6 J, then the value of c is

The correct option is C 6We know that work done by a force is given by, W=→F.→d=(3^i+c^j+2^k).(−4^i+2^j+3^k) =−12+2c+6=2c−6 From the question, 2c−6=6 ∴c=6

A force, $\to F = 3^i + c^j + 2^k$ acting on a particle causes a displacement $\to d = - 4^i + 2^j + 3^k .$ If the work done is $6 J$ , then the value of $c$ is

The correct option is C 6
We know that work done by a force is given by,
$W = \to F . \to d = (3^i + c^j + 2^k) . (- 4^i + 2^j + 3^k)$
$= - 12 + 2 c + 6 = 2 c - 6$
From the question,
$2 c - 6 = 6 ∴ c = 6$