A force →F=3^i+c^j+2^k acting on a particle causes a displacement →S=−4^i+2^j−3^k in its own direction. If the work done by the force is 6J, then the value of c will be
A
12
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B
1
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C
6
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D
0
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Solution
The correct option is A12 Workdone =→F.→S=6J
Given →F=(3i+cj+2k)N →S=(−4i+2j−3k)m W=→F.→S=6 ⇒3(−4)+c(2)+2(−3)=6 ⇒−12+2c−6=6 ⇒2c=24 c=12