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Question

A force F=6x^i+2y^j displaces a body from r1=3^i+8^j to r2=5^i4^j. Find the work done by the force.

A
0 J
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B
75 J
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C
64 J
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D
16 J
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Solution

The correct option is A 0 J
Given, force F=6x^i+2y^j
Initial position, r1=3^i+8^j and final position r2=5^i4^j
We know that, work done
W=F.ds=F.(dx^i+dy^j)
=S2S1(6x^i+2y^j).(dx^i+dy^j)
=536x dx+482y dy
=[3x2]53+[y2]48
=(7527)+(1664)=0

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