A force →F=[y^i+x^j]N acts on a particle moving in x−y plane starting from the point (3,5)m, the particle is taken along a straight line to (5,7)m. The work done by the force( in J upto two decimals) is:
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Solution
Work done by variable force is W=∫→F.(dx^i+dy^j) W=[∫ydx+∫xdy]=∫d(xy) W=∫(5,7)(3,5)d(xy)=35−15=20 J