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Question

A force F=[y^i+x^j]N acts on a particle moving in xy plane starting from the point (3,5)m, the particle is taken along a straight line to (5,7)m. The work done by the force( in J upto two decimals) is:

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Solution

Work done by variable force is
W=F.(dx^i+dy^j)
W=[ydx+xdy]=d(xy)
W=(5,7)(3,5)d(xy)=3515=20 J

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