A force shown in the F-x graph is applied to $5 k g$ cart, which then coasts up a ramp as shown. The maximum height, $y_{m a x}$ reached by the cart is $(g = 10 m / s^{2})$

1 m

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2 m

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3 m

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5 m

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Solution

The correct option is B $2 m$
We know,
Work done $= \int F . d x$ (Area under F,x curve)

Here till x=5m,
Work done on body $= \frac{1}{2} \times 50 \times 4 = 100 J$

$W . D = Δ K . E$

As initially body was at rest,

$K E_{f} = 100$

Let max height achieved $= y m$

$100 + 0 = 0 + m g y$

$y = \frac{100}{10 \times 5} = 2 m$

Option $B$ is the correct answer

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A force shown in the F-x graph is applied to 5kg cart, which then coasts up a ramp as shown. The maximum height, ymax reached by the cart is (g=10m/s2)

The correct option is B 2mWe know,Work done=∫F.dx (Area under F,x curve)Here till x=5m,Work done on body=12×50×4=100 JW.D=ΔK.EAs initially body was at rest,KEf=100Let max height achieved=y m100+0=0+mgyy=10010×5=2 mOption B is the correct answer

A force shown in the F-x graph is applied to $5 k g$ cart, which then coasts up a ramp as shown. The maximum height, $y_{m a x}$ reached by the cart is $(g = 10 m / s^{2})$