A force-time graph for a linear motion is shown in the figure where the segments are circular. The linear momentum gained between zero and 8 second is :
A
−2π Newton seconds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0 Newton seconds
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4π Newton seconds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
−6π Newton seconds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A0 Newton seconds Area of F-t graph is the change in momentum. Let's divide the graph into 3 parts viz., 1) 0 < t < 2 2) 2 < t < 6 3) 6 < t < 8 In part 1, 2, and 3, the areas are −Π,2Π,−Π So, Totalmomentumchange=−Π+2Π+−Π=0