A force F-3-c-2k-N acting on a particle causes a displacement S-4-2-3k- m- lf the work done is 6 Joule- the value of c is-

The correct option is B 12 W= F⃗·S⃗= 6 F⃗ = 3î + cĵ + 2k̂ S⃗= 4î + 2ĵ 3k̂ ⇒ 3×( 4 )+ 2c+ 2×( 3 )= 6 ⇒ #160;2c= 24 ⇒ c= 12 ...

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Work Done as Dot Product

A force F⃗=...

Question

A force $\to F = 3^i + c^j + 2^k N$ acting on a particle causes a displacement $\to S = - 4^i + 2^j - 3^k$ m. lf the work done is 6 Joule, the value of c is:

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\to F = 3^i + c^j + 2^k

\to S = - 4^i + 2^j + 3^k

6

c

\to F = 3^i + c^j + 2^k

\to S = - 4^i + 2^j - 3^k

6 J

c

\to F = 3^i + c^j + 2^k

\to d = - 4^i + 2^j + 3^k .

6 J

c

\to F = 3^i + c^j + 2^k

\to d = - 4^i + 2^j + 3^k .

6 J

c

F = (3^i + c^j + 2^k) N

\to S = (- 4^i + 2^j - 3^k) m

6 J

^{'} c^{'}

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