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Question
A force →F=5^i−3^j+2^k moves a particle from →r1=2^i+7^j+4^k to →r2=5^i+2^j+8^k then work done is:
A force →F=5^i−3^j+2^k moves a particle from →r1=2^i+7^j+4^k to →r2=5^i+2^j+8^k then work done is:
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Solution
The correct option is B 38 units
→s=→r2−→r1 =(5^i+2^j+8^k)−(2^i+7^j+4^k) =3^i−5^j+4^k
Work done is given by W=→F.→s =(5^i−3^j+2^k).(3^i−5^j+4^k) =15+15+8=38 units
→s=→r2−→r1 =(5^i+2^j+8^k)−(2^i+7^j+4^k) =3^i−5^j+4^k
Work done is given by W=→F.→s =(5^i−3^j+2^k).(3^i−5^j+4^k) =15+15+8=38 units
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