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Byju's Answer

Standard XII

Chemistry

Longest Chain Rule

A force F⃗ ...

Question

A force $\to F$ acting on an electric charge q in presence of an electromagnetic field, moves the charge parallel to the magnetic field with velocity $\to v$ . Then, $\to F$ is equal to(where $\to E$ and $\to B$ are electric field and magnetic field, respectively) ___________.

q \to E

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q (\to v \times \to B)

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q (\to v \times \to E)

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q \to B

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Solution

The correct option is A $q \to E$
Net Lorentz force acting on the particle $\to F = q (\to E + \to v \times \to B)$
Since, velocity is parallel to magnetic field.
$⟹ \to v \times \to B = 0$
Thus force acting on the particle $\to F = q \to E$

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A force →F acting on an electric charge q in presence of an electromagnetic field, moves the charge parallel to the magnetic field with velocity →v. Then, →F is equal to(where →E and →B are electric field and magnetic field, respectively) ___________.

The correct option is A q→ENet Lorentz force acting on the particle →F=q(→E+→v×→B)Since, velocity is parallel to magnetic field. ⟹ →v×→B=0Thus force acting on the particle →F=q→E

A force $\to F$ acting on an electric charge q in presence of an electromagnetic field, moves the charge parallel to the magnetic field with velocity $\to v$ . Then, $\to F$ is equal to(where $\to E$ and $\to B$ are electric field and magnetic field, respectively) ___________.

The correct option is A $q \to E$
Net Lorentz force acting on the particle $\to F = q (\to E + \to v \times \to B)$
Since, velocity is parallel to magnetic field.
$⟹ \to v \times \to B = 0$
Thus force acting on the particle $\to F = q \to E$