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Standard XII

Physics

Direction of Friction

A force f⃗=...

Question

A force $\to f = (^i + 3^j) N$ acts on a body at a point which position from axis is given by $\to r = (3^i +^j)$ the torque on body is

8^k

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- 8^k

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6^k

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Solution

The correct option is B $- 8^k$
$\begin{matrix} Torque τ & = ¯ γ \times ¯ f = (^i + 3^j) \times (3^i +^j) \end{matrix}$

$Hence option B is correct$

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Similar questions

Q. if force

\to F = (^i + 3^j) N

acts on a body at a point whose distance from the axis of rotation is given by

\to r = (3^i +^j) N

then torque acting on the body is:

Choose the correct option for the two given statements from the options:

Statement-

1

: The torque about the point

2^i +^j -^k

of a force represented by

4^i +^k

acting through the point

^i -^j + 2^k

- 2^i + 13^j + 8^k

Statement-

2

: The torque of a force

\to F

about a point

P

\to r \times \to F

where

\to r

is the vector from the point

P

to any point

\to a

on the line of action

L

\to F

Q. Let a force

\to F

be acting on a body free to rotate about a point O and let

\to r

the position vector of any point P on the line of action of the force. Then torque

\to t

of this force about point O is defined as

\to t = \to r \times \to F

Given,

\to F = (2^i + 3^j -^k) N a n d \to r = (^i -^j + 6^k) m

Find the torque of this force.

Q. Let a force

\to F

be acting on a body free to rotate about a point

O

and let

\to r

be the position vector of any point

P

on the line of action of the force. Then torque

\to τ

of this force about point

O

is defined as :

\to τ = \to r \times \to F

Given,

\to F = (2^i + 3^j -^k) N

and

\to r = (^i -^j + 6^k) m

. Find the torque of this force.

Q. Two forces

_{1} = 2^i - 5^j - 6^k

and

_{2} = -^i + 2^j -^k

are acting on a body at a point

(1, 1, 0)

and

(0, 1, 2)

respectively. Find the torque acting on the body about the point

(- 1, 0, 1)

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A force →f=(^i+3^j)N acts on a body at a point which position from axis is given by →r=(3^i+^j) the torque on body is

The correct option is B −8^k Torque τ=¯γ×¯f=(^i+3^j)×(3^i+^j) Hence option B is correct

A force $\to f = (^i + 3^j) N$ acts on a body at a point which position from axis is given by $\to r = (3^i +^j)$ the torque on body is

The correct option is B $- 8^k$
$\begin{matrix} Torque τ & = ¯ γ \times ¯ f = (^i + 3^j) \times (3^i +^j) \end{matrix}$

$Hence option B is correct$