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Question

A force F=^i+4^j acts on block shown. Determine the force of friction acting on the block is :
863564_facc77b587224a019336e5bf81705bc2.png

A
^i
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B
1.8^i
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C
2.4^i
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D
3^i
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Solution

The correct option is A ^i
Normal force,

N=(mg4)^j=(104)^j=6^j

Limiting friction,

f=μN=0.3×6(^j)=1.8(^i)

Here horizontal force = 1N less than the limiting frictional value hence frictional force acting F = horizontal force of friction

f=1(^i)N

983332_863564_ans_c266d42a8519481a85124a161c7cc380.png

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