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Byju's Answer
Standard XII
Physics
Pulley
A force F⃗ ...
Question
A force
→
F
=
^
i
+
4
^
j
acts on block shown. Determine the force of friction acting on the block is :
A
−
^
i
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B
−
1.8
^
i
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C
−
2.4
^
i
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D
−
3
^
i
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Solution
The correct option is
A
−
^
i
Normal force,
N
=
(
m
g
−
4
)
^
j
=
(
10
−
4
)
^
j
=
6
^
j
Limiting friction,
f
=
μ
N
=
0.3
×
6
(
−
^
j
)
=
1.8
(
−
^
i
)
Here horizontal force =
1
N
less than the limiting frictional value hence frictional force acting F = horizontal force of friction
f
=
1
(
−
^
i
)
N
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