A force F- makes an angle 20- with another force F- The resultant of two forces is-

The correct option is A 2F cos 10^∘ R^2 = F^2 + F^2 + 2F^2 cos 20^∘ #160; #160; #160; = 2F^2( 1+ cos 20^∘) = 2F^2 × 2 cos^2 10^∘ = ...

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Standard XII

Physics

Net Force

A force F⃗ ...

Question

A force $\to F$ makes an angle $20^{\circ}$ with another force $\to F$ . The resultant of two forces is:

F c o s 20^{\circ}

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2 F c o s 20^{\circ}

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2 F c o s 10^{\circ}

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F c o s 10^{\circ}

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Solution

The correct option is A $2 F c o s 10^{\circ}$
$R^{2} = F^{2} + F^{2} + 2 F^{2} cos 20^{\circ}$
$= 2 F^{2} (1 + cos 20^{\circ}) = 2 F^{2} \times 2 {cos}^{2} 10^{\circ} = 4 F^{2} {cos}^{2} 10^{\circ}$

$\Rightarrow R = 2 F cos 10^{\circ}$

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A force →F makes an angle 20∘ with another force →F. The resultant of two forces is:

The correct option is A 2Fcos10∘R2=F2+F2+2F2cos20∘ =2F2(1+cos20∘)=2F2×2cos210∘=4F2cos210∘⇒R=2Fcos10∘

A force $\to F$ makes an angle $20^{\circ}$ with another force $\to F$ . The resultant of two forces is:

The correct option is A $2 F c o s 10^{\circ}$
$R^{2} = F^{2} + F^{2} + 2 F^{2} cos 20^{\circ}$
$= 2 F^{2} (1 + cos 20^{\circ}) = 2 F^{2} \times 2 {cos}^{2} 10^{\circ} = 4 F^{2} {cos}^{2} 10^{\circ}$

$\Rightarrow R = 2 F cos 10^{\circ}$