A force vector appliedon a body is given by F-6 -8 -10 k- and acquires an acceleration 1 ms 2 Then the mass of the body isA- 10 - akg B- 2 -10 kgC- 10 kgD- 20 kg

The correct option is A m = |F̅|/a = √(6^2+( 8)^2+10^2)/1 = √(36+64+100) = √(200) = 10 √(2)kg ...

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Standard XII

Physics

Net Force

A force vecto...

Question

A force vector appliedon a body is given by $\to F = 6^i - 8^j + 10^k$ and acquires an acceleration $1 m s^{2}$ Then the mass of the body is

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10 kg

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20 kg

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Solution

The correct option is A

$m = \frac{| ¯ F |}{a} = \frac{\sqrt{6^{2} + (- 8)^{2} + 10^{2}}}{1} = \sqrt{36 + 64 + 100} = \sqrt{200} = 10 \sqrt{2} k g$

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A force vector appliedon a body is given by →F=6^i−8^j+10^k and acquires an acceleration 1 ms2 Then the mass of the body is

The correct option is A m=|¯F|a=√62+(−8)2+1021=√36+64+100=√200=10√2kg

A force vector appliedon a body is given by $\to F = 6^i - 8^j + 10^k$ and acquires an acceleration $1 m s^{2}$ Then the mass of the body is

The correct option is A

$m = \frac{| ¯ F |}{a} = \frac{\sqrt{6^{2} + (- 8)^{2} + 10^{2}}}{1} = \sqrt{36 + 64 + 100} = \sqrt{200} = 10 \sqrt{2} k g$