A fork of unknown frequency gives 4 beats/sec when sounded with another fork of frequency 256Hz. The fork is now loaded with a piece of wax and again 4 beats/sec are heard .Then the frequency of the unknown fork is :
A
256 Hz
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B
252 Hz
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C
264 Hz
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D
260 Hz
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Solution
The correct option is B 260 Hz on putting wax on tuning fork prong's its frequency decreases , as no of beats after reduction in frequency are same means that frequency of unknown fork is higher than given fork .