A fork P of unknown frequency gives six beats per second when sounded with another fork Q of frequency 260 Hz. The fork P is now loaded with a piece of wax and again six beats per second is heard, then frequency of fork P is
A
260 Hz
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B
254 Hz
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C
266 Hz
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D
250 Hz
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Solution
The correct option is C266 Hz Beats frequency =fP−fQ fP−260=±6 fP=260±6
Thus possible frequency of fork P are 260±6=266 Hz or 254 Hz,
As frequency decreases on loading, therefore original frequency of fork P is 266 Hz.