CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A fork P of unknown frequency gives six beats per second when sounded with another fork Q of frequency 260 Hz. The fork P is now loaded with a piece of wax and again six beats per second is heard, then frequency of fork P is

A
260 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
254 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
266 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
250 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 266 Hz
Beats frequency =fPfQ
fP260=±6
fP=260±6
Thus possible frequency of fork P are 260±6=266 Hz or 254 Hz,
As frequency decreases on loading, therefore original frequency of fork P is 266 Hz.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sound Properties
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon