A fort has provision for $150$ men for $45$ days. After $10$ days $25$ men left the fort . How long will the food last at the same rate?

Open in App

Solution

The remaining food would last $(45 - 10) = 35$ days
Number of remaining men $= 150 - 25 = 125$
$150$ men $= 35$ days
$125$ men $= x$ days
$\Rightarrow \frac{150 \times 35}{125} = x$
$∴ x = 42$
Hence the food will long last at the rate of $42$ days.

Suggest Corrections

Similar questions

In a fort 150 men had provisions for 45 days. After 10 days, 25 men left the fort. How long would the food last at the same rate?

Q. A fort had provisions for 600 men for 180 days. After 40 days, 100 men left the fort. How long will the food last at the same rate ?

Q. A fort had provision of food for

150

men for

45

days. After

10

days,

25

men left the fort, The number of days for which the remaining food will last, is

Question 04.A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is:

Q. In a fort, 200 men had provision for 60 days. After 20 days, 40 men were shifted to other places. How long will the provision last for remaining men at the same rate?

Join BYJU'S Learning Program

A fort has provision for 150 men for 45 days. After 10 days 25 men left the fort . How long will the food last at the same rate?

The remaining food would last (45−10)=35daysNumber of remaining men =150−25=125150 men=35 days125 men =x days⇒150×35125=x∴x=42 Hence the food will long last at the rate of 42 days.

A fort has provision for $150$ men for $45$ days. After $10$ days $25$ men left the fort . How long will the food last at the same rate?

The remaining food would last $(45 - 10) = 35$ days
Number of remaining men $= 150 - 25 = 125$
$150$ men $= 35$ days
$125$ men $= x$ days
$\Rightarrow \frac{150 \times 35}{125} = x$
$∴ x = 42$
Hence the food will long last at the rate of $42$ days.