A four bar mechanism is made up of links of length 100, 200, 300 and 350mm. If the 350 mm link is fixed, the number of links that can rotate fully is .
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Solution
s=100,p=200,l=350,q=300 (s+l)=350+100=450<(p+q) 450<200+300 450<500
Grashof law is satisfied.
350 mm link is fixed.
Then, shortest link (=100 mm) is adjacent to fixed link, so it will give crank only.
POINT TO REMEMBER
Accoding to Grashof's law, for continuous relative motion s+l≤p+q So, in this problem, s + l < p + q is satisfied
If shortest link, s is fixed, mechanism will be double crank.
If link adjacent of shortest link is fixed, mechanism will be crank-rocker type.