You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Ampere's Circuital Law

A frame CDE...

Question

A frame $C D E F$ is laced in a region where a magnetic field $\to B$ is present. A rod of length one metre moves with constant velocity $20 m / s$ and strength of magnitude field is one tesia. The power spent in the process is (take $R = 0.2 Ω$ and all other wires and rod have zero resistance)

1 k W

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 k W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 k W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 k W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $1 k W$
Since Force applied on wire will be $F = I l \times B$ . Here we dont know V to find out Current I so that we can calculate Force $F$ From which Power $P = F . V$ But if we assume V= 1Volt Then $I = 1 / 0.2 = 50 A$ and $F = 50 \times 1 \times 1 = 50 N$ And power $P = 50 \times 20 = 1000 W = 1 k W$

Suggest Corrections

Similar questions

Q. A rod

P Q

of length

1 m

is placed on the frame

C D E F

. This setup is placed in a space where a uniform magnetic field

\to B

, of magnitude

1 T

exist. The rod moves with a constant velocity of

20 m/s

. The power spent by external force to keep the rod moving with constant velocity is -

Given,

R = 0.2 Ω

and all other wires and rod have zero resistance.

Q. A frame

CDEF

is placed in a region where a magnetic field

\to B

is into the plane of the loop. A rod of length

1 m

moves with constant velocity

20 {ms}^{- 1}

and strength of magnetic field is

1 T

. The power delivered in the process is-

[The value of

R = 0.2 Ω

and other parts have negligible resistance]

Q. A frame

PQRS

is placed in a region where magnetic field

B

is present, as shown in the figure. A rod of length

2 m

moves with a constant velocity

25 m/s

and the strength of the magnetic field inside the plane of paper is

0.1 T

. If the resistance of the rod is

10 Ω

and the resistance of the frame is negligible, then calculate the power spent in this process

X X^{'}

is a conducting rod which can slide, freely on U shaped frame with resistance

R

. A constant magnetic field

B

acts perpendicular to the frame. If a constant force is applied on a string connected to the rod as shown in figure, such that the rod moves with a constant velocity of

V_{0} .

If the direction of velocity and magnetic field are reversed without changing their magnitudes and if the constant force is applied to move to rod

X X^{'}

with the same constant speed, then

Q. A conducting rod of length

l

is moving in a transverse magnetic field of strength

B

with velocity

v

. The resistance of the rod is

R

. The current in the rod is

Join BYJU'S Learning Program

A frame CDEF is laced in a region where a magnetic field →B is present. A rod of length one metre moves with constant velocity 20 m/s and strength of magnitude field is one tesia. The power spent in the process is (take R=0.2Ω and all other wires and rod have zero resistance)

The correct option is A 1 kWSince Force applied on wire will be F=Il×B. Here we dont know V to find out Current I so that we can calculate Force F From which Power P=F.V But if we assume V= 1Volt Then I=1/0.2=50A and F=50×1×1=50N And power P=50×20=1000W=1kW

A frame $C D E F$ is laced in a region where a magnetic field $\to B$ is present. A rod of length one metre moves with constant velocity $20 m / s$ and strength of magnitude field is one tesia. The power spent in the process is (take $R = 0.2 Ω$ and all other wires and rod have zero resistance)