A freei pitch ball of mass 6 gram carries a positive charge of (1/3 )* 10 -7 coulomb what must be nature and magnitude of charge that should be given to second pitch ball fixed 5 cm vertically below the former baseball so that the upper bonus stationery.
Mass of the pith ball, m = 6 g = .006 kg
Charge on it is, q = 1/3 × 10-7 C
Let Q be the charge on the other pith ball placed at 5 cm or 0.05 m below.
The weight of the upper pith ball is balanced by the electrostatic repulsion between the balls.
mg = kqQ/r2
=> (0.006)(9.8) = (9 × 10^9)( 1/3 × 10-7)Q/(0.05^2)
=> Q = 0.0049 c