Question

A freely falling body starting from rest, travel _____ of total distance in $5th$ Second

• A. $8\%$
• B. $12\%$
• C. $25\%$
• D. $36\%$

Answer 1

The correct option is D $36\%$

Distance fall in first $5$ second is $s=\frac{g{5}^2}{2}=\frac{25g}{2}$

Distance fall in first $4$ second is $s_0=\frac{g{4}^2}{2}=\frac{16g}{2}$

so ditance covered in $5^{th}$ second will be $s-s_0=\frac{9g}{2}$

so percentage of total distance covered will be $\frac{9g/2}{25g/2}\times 100=36$%