A frequency distribution table which gives the weights of 38 students of a class is given. Convert it into a continuous grouped frequency.

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Solution

First step to convert a non-continuous data into a continuous is to calculate the adjustment factor.
Adjustment factor :

Add 0.5 to the upper limit and subtract 0.5 from lower limit of the class interval.

Let's take the class ‘31-35’

New class interval is:
Upper limit + 0.5 = 35 + 0.5 = 35.5
Lower limit - 0.5 = 31 - 0.5 = 30.5

Please note, 30.5 is included in the class interval 30.5 - 35.5 and 35.5 is included in the class interval 35.5 - 40.5.

The same goes for all the other intervals as well.

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Similar questions

Q. Collect the data of weights of students in your class. prepare a grouped frequency distribution table.

Q. The following table gives the frequency distribution of the percentage of marks obtained by 2300 students in a competitive examination.

Marks obtained (in per cent)	11−20	21−30	31−40	41−50	51−60	61−70	71−80
Number of students	141	221	439	529	495	322	153

(a) Convert the given frequency distribution into the continuous form.

(b) Find the median class and write its class mark.

(c) Find the modal class and write its cumulative frequency.

Q. The class intervals in a frequency distribution are:
40 – 44, 45 – 49, 50 – 54,........ If the frequency distribution, is converted into a continuous frequency distribution then the class intervals are _________.

Question 95(ii)

The weights (in kg) of 30 students of a class are as follows :
39, 38, 36, 38, 40, 42, 43, 44, 33, 33, 31, 45, 46, 38, 37,
31, 30, 39, 41, 41, 46, 36, 35, 34, 39, 43, 32, 37, 29, 26
Prepare a frequency distribution table using one class interval as (30-35), 35 not included.
Which class has the maximum frequency ?

Q. The given table represents the age-wise distribution of
teachers working at a school. Convert it into a continuous
grouped frequency distribution.

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