A fresh $H_{2} O_{2}$ solution is labelled 11.2 V. This solution has the same concentration as a solution which is:

3.4% (w/v)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.4% (V/V)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3.4% (w/w)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 3.4% (w/v)
Molarity of $H_{2} O_{2} = \frac{v o l u m e s t r e n g t h}{11.2}$
$= \frac{11.2}{11.2} = 1$
Now, %(w/v) $= \frac{w e i g h t o f s o l u t e i n g}{v o l u m e o f s o l u t i o n i n m L} \times 100$
$= \frac{M o l a r i t y}{1} \times m o l . ω t . o f s o l u t e \times \frac{1}{10} = 1 \times 34 \times \frac{1}{10} = 3.4 %$

Suggest Corrections

Similar questions

A fresh $H_{2} O_{2}$ solution is labelled 11.2V. This solution has the same concentration as a solution which is:

Q. A fresh

H_{2} O_{2}

solution is labeled as

11.2 V

. Calculate its concentration in wt/vol percent.

Q. A sample of

H_{2} O_{2}

solution labelled as “28 volume” has density of 265 g/L. Mark the correct option(s) representing concentration of same solution in other units:

In a reaction,200ml of hydrogen peroxide sample solution (at STP) liberated 3 litres of oxygen. What is the concentration (in % w/v) of the $H_{2}$ $O_{2}$ in the sample?

Q. The concentration of a solution of

H_{2} O_{2}

is 6.8%(w/V) then the volume concentration of the solution is:-

Join BYJU'S Learning Program

A fresh H2O2 solution is labelled 11.2 V. This solution has the same concentration as a solution which is:

The correct option is A 3.4% (w/v)Molarity of H2O2=volume strength11.2 =11.211.2=1 Now, %(w/v) =weight of solute in gvolume of solution in mL×100 =Molarity1× mol.ωt. of solute×110=1×34×110=3.4%

A fresh $H_{2} O_{2}$ solution is labelled 11.2 V. This solution has the same concentration as a solution which is: