A freshly obtained precipitate of $S n O_{2}$ is peptized by little of $K O H$ to give a sol. The sol particles may be represented as :

[S n O_{2}] K^{+}

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[S n P_{2}] O H^{-}

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[S n O_{2}] S n^{4 +}

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[S n O_{2}] S n O_{3}^{2 -}

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Solution

The correct option is D $[S n O_{2}] S n O_{3}^{2 -}$
The reaction is as follows:
$S n O_{2} (s) + 2 K O H (a q) \to K_{2} S n O_{3} (a q) + H_{2} O$
$S n O_{3}^{2 -}$ ions would be preferentially adsorbed by $S n O_{2}$ particles.

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