The correct option is B 12 h
Let's say the permissible level of intensity of radiation, that is Activity is A, so initially we have 64A activity.
We need to calculate the time taken to drop the activity from 64A to A.
We know, A = A0e−λt
A0 is 64A here. So after subtituting this we get,
e−λt=164
Or,
eλt=64.
Which gives,
λt=In 64.
Or,
t=In 64λ………1)
Now we have half-life,t1/2 = 2h
Which gives, λ = In 2t1/2= In 22h
Now putting this value in equation 1)
t = In 64λ=In 64In 2×2h
Or,
t = 6 In 2In 2×2h=12h.