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Standard XII

Chemistry

Molar and Specific Heat Capacity

A frictionles...

Question

A frictionless piston-cylinder device contains a gas initially at 0.8 MPa and 0.015 $m^{3}$ . It expands quasistatically at constant temperature to a final volume of 0.030 $m^{3}$ . The work output (in kJ) during this process will be

8.32

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12.00

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554.67

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8320.00

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Solution

The correct option is A 8.32
(a)
Given data for constant temperature process:
$p_{1} = 0.8 M P a = 800 k P a$
$V_{1} = 0.015 m^{3}$
$V_{2} = 0.030 m^{3}$
We know that work done for constant temperature process,
$W = p_{1} V_{1} l o g_{e} \frac{V_{2}}{V_{1}}$
$800 \times 0.015 l o g_{e} \frac{0.030}{0.015}$
$= 8.317 k J \approx 8.32 k J$

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A frictionless piston-cylinder device contains a gas initially at 0.8 MPa and 0.015 m3. It expands quasistatically at constant temperature to a final volume of 0.030 m3. The work output (in kJ) during this process will be

The correct option is A 8.32(a) Given data for constant temperature process: p1=0.8MPa=800kPa V1=0.015m3 V2=0.030m3 We know that work done for constant temperature process, W=p1V1logeV2V1 800×0.015loge0.0300.015 =8.317kJ≈8.32kJ

A frictionless piston-cylinder device contains a gas initially at 0.8 MPa and 0.015 $m^{3}$ . It expands quasistatically at constant temperature to a final volume of 0.030 $m^{3}$ . The work output (in kJ) during this process will be