A frictionless wire AB is fixed on a circular frame of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to B is

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Solution

The correct option is C

$∠ A B C = 90^{0} Acceleration along AB is a = g c o s θ Distance travelled is A B = 2 R C o s θ We have 2 R C o s θ = \frac{1}{2} \times g c o s θ t^{2} \Rightarrow t = 2 \sqrt{\frac{R}{g}}$

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A frictionless wire AB is fixed on a circular frame of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to B is

The correct option is C ∠ABC=900Acceleration along AB is a=gcos θDistance travelled is AB=2R CosθWe have 2R Cosθ=12×g cosθ t2⇒t=2√Rg

The correct option is C

$∠ A B C = 90^{0} Acceleration along AB is a = g c o s θ Distance travelled is A B = 2 R C o s θ We have 2 R C o s θ = \frac{1}{2} \times g c o s θ t^{2} \Rightarrow t = 2 \sqrt{\frac{R}{g}}$