A Friedel-Crafts reaction of benzene with chloroform produces:

C_{6} H_{5} {C H C l}_{2}

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C_{6} H_{5} - C l | C | H - C_{6} H_{5}

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C_{6} H_{5} - C_{6} H_{5} | C | H - C_{6} H_{5}

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Solution

The correct option is D $C_{6} H_{5} - C_{6} H_{5} | C | H - C_{6} H_{5}$
Hence, option $C$ is correct.

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C_{6} H_{6} \to C_{6} H_{5} {C H}_{3}

C_{6} H_{5} - C H_{2} - C H = C H_{2} + H B r \to

C_{6} H_{5} - C H = C H_{2} + H B r P e r o x i d e - ---- \to

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