A frisbee disc has a diameter of 26 inches. The distance covered by the disc in 3 revolutions is inches.
(Take value of π = 22/7)

246.24

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245.14

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247.34

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Solution

The correct option is B 245.14
$Diameter of the disc, d = 26 i n c h e s$
$Radius of the disc, r = 26 \div 2 = 13 i n c h e s$

$Distance covered by = No. of revolution$
$the disc x Perimeter of the disc$

$= 3 \times 2 π r$
$= 3 \times 2 \times \frac{22}{7} \times 13$
= 245.14 inches

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A frisbee disc has a diameter of 26 inches. The distance covered by the disc in 3 revolutions is inches. (Take value of π = 22/7)

The correct option is B 245.14Diameter of the disc, d=26 inches Radius of the disc, r=26÷2=13 inches Distance covered by = No. of revolution the disc x Perimeter of the disc =3×2πr =3×2×227×13 = 245.14 inches

A frisbee disc has a diameter of 26 inches. The distance covered by the disc in 3 revolutions is inches.
(Take value of π = 22/7)

The correct option is B 245.14
$Diameter of the disc, d = 26 i n c h e s$
$Radius of the disc, r = 26 \div 2 = 13 i n c h e s$

$Distance covered by = No. of revolution$
$the disc x Perimeter of the disc$

$= 3 \times 2 π r$
$= 3 \times 2 \times \frac{22}{7} \times 13$
= 245.14 inches