Question

A fruit seller bought some oranges at 4 for Rs. 3 and an equal number at 5 for Rs. 3. He mixed the two lots and sold these at 90 paise each. Find the gain or loss per cent.
C.P. of 1 orange of 1st kind = $Rs.\frac{3}{4}$
= Rs. 0.75
C.P. of 1 orange of 2nd kind = $Rs.\frac{3}{5}$
= Rs. 0.60
On mixing, C.P. of 2 oranges = Rs. 0.75 + Rs 0.60 = Rs 1.35 and S.p. of 2 oranges = $2\times 90$ paise
= Rs. 1.80.

• A. $32\frac{1}{3}\%$
• B. $33\frac{1}{3}\%$
• C. $33\frac{2}{3}\%$
• D. $3\frac{1}{3}\%$

Answer 1

The correct option is B $33\frac{1}{3}\%$

Lets fruit seller brought a lot of 100 oranges
C.P. of 100 orange of 1st kind = Rs.$\frac{3}{4}\times 100$
= Rs$.(0.75\times 100)$=Rs 75
C.P. of 100 orange of 2nd kind = Rs.$\frac{3}{5}\times 100$
= Rs$.(0.60\times 100)$=Rs 60
On mixing, C.P. of 200 oranges = Rs. 75 + Rs 60 = Rs 135 and S.p. of 200 oranges =$200\times 0.90$=Rs 180
Profit = 180-135=Rs 45
% of profit=$\frac{45\times 100}{135}=33\frac{1}{3}$%