A fruit-seller sells $4$ oranges for Rs. $3$ , gaining $50 %$ . Find C.P. of $4$ oranges.

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Solution

Given, S.P of $4$ oranges $= R s 3$
And for these $4$ oranges, Profit $= 50$ %
So, Profit % $= \frac{S . P . - C . P .}{C . P .} \times 100 = 50$

$=> \frac{3 - C . P}{C . P} \times 100 = 50$

$=> 3 - C . P . = 0.5 C . P .$
$=> 1.5 C . P . = 3$
$C . P . = 2$
Hence, cost of $4$ oranges $= R s 2$

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Similar questions

A fruit-seller sells 4 oranges for Rs.3, gaining 50%. Find : (i) C.P. of 4 oranges. (ii) C.P. of one orange. (iii) S.P. of one orange (iv) profit made by selling one orange (v) number of oranges need to be bought and sold in order to gain Rs.24.

Q. A fruit-seller sells

4

oranges for Rs.

3

, gaining

50 %

If S.P. of one orange is

0.75

Rs, then type

1

or else type

0

Q. A fruit-seller sells

4

oranges for Rs.

3

, gaining

50 %

. Number of oranges bought and sold in order to gain Rs. 24.

Q. A fruit-seller sells

4

oranges for Rs.

3

and gains

50 %

. Find the profit made by selling one orange.

A fruit seller sells 4 oranges for ₹3. gaining 50%. The cost price of 4 oranges is ₹ ___.

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A fruit-seller sells 4 oranges for Rs. 3, gaining 50%. Find C.P. of 4 oranges.

Given, S.P of 4 oranges =Rs3 And for these 4 oranges, Profit =50 % So, Profit % =S.P.−C.P.C.P.×100=50=>3−C.PC.P×100=50 =>3−C.P.=0.5C.P.=>1.5C.P.=3C.P.=2Hence, cost of 4 oranges =Rs2

A fruit-seller sells $4$ oranges for Rs. $3$ , gaining $50 %$ . Find C.P. of $4$ oranges.

Given, S.P of $4$ oranges $= R s 3$
And for these $4$ oranges, Profit $= 50$ %
So, Profit % $= \frac{S . P . - C . P .}{C . P .} \times 100 = 50$

$=> \frac{3 - C . P}{C . P} \times 100 = 50$

$=> 3 - C . P . = 0.5 C . P .$
$=> 1.5 C . P . = 3$
$C . P . = 2$
Hence, cost of $4$ oranges $= R s 2$