A fruit seller sells 60 percent of Oranges he had and throws away 15 percent of the remainder. Next day he sells 50 percent of the remainder and throws away the rest. What percent of his fruit seller does he throw?
A
15%
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B
20%
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C
21%
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D
23%
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Solution
The correct option is D 23% Let the number of oranges be 100. On the first day he sells 60% oranges, i.e., 60 oranges. Remaining = 40. He throws 15% of the remaining i.e., 15% of 40 = 6. Now he has 40−6=34 oranges The next day he throws 50% of the remaining 34 oranges i.e., 17. Therefore, in total he throws 6+17= 23 oranges = 23% oranges