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Question

A frustrum of a right circular cone has a diameter of base 20cm, of top 12cm, and height 3cm. Find the area of its whole surface and volume.

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Solution

D1=20cm,R1=10cm
D2=12cm,R2=6cm
h=3cm
Volume of frustum =13πh(R21+R22+R1R2)=13×227×3[102+62+10×6]
=227×196=616cm3
Let slant height, be l. Then,
l=(R1R2)2+h2=(106)2+32=16+9=5cm
TSA of frustum of cone =π(R1+R2)l+π(R21+R22)
=227[10+6]×5+227(102+62)
=227[80+1360]=227×216=678.85cm2

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