Question

A full hydrodynamic bearing has a journal diameter of 60 mm and a radial load of 1000 N. If journal speed is 1500 rpm and the length of the journal is 25 mm. The standard value of radial clearance is $25\mu m,$ what will be the flow of lubricant if the flow variable is given by 4.29.

• A. $2011m{m}^3/sec$
• B. $2590m{m}^3/sec$
• C. $1009m{m}^3/sec$
• D. $1510m{m}^3/sec$

Answer 1

The correct option is A $2011m{m}^3/sec$

$\frac{Q}{rC{n}_{s}l}=4.29$

$Q=4.29\times \left(\frac{60}{2}\right)\times \left(0.025\right)\times \left(\frac{1500}{60}\right)\times \left(25\right)$

$Q=2010.9375m{m}^3/sec\simeq 2011m{m}^3/sec$