CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A function becomes $$\dfrac{1}{4}$$, when $$2$$ is subtracted  from the numerator and $$3$$ is added to the denominator. Represent this situation as a linear equation in two variables. Also find two solutions for this.


Solution

$$\cfrac{x-2}{y+3}=\cfrac{1}{4}\\ \Rightarrow 4x-8=y+3\\ \Rightarrow 4x-y=3+8\\ \Rightarrow 4x-y=11\\ \therefore 4x-y-11=0$$
 is a linear equation representing $$x$$ and $$y$$ as two variables.
Now, 
When $$x=0, y=-11$$ and when $$y=0$$, $$x=\dfrac{11}{4}$$
Hence, $$(0,-11)$$ and $$(\dfrac{11}{4},0)$$ are the two solutions for this equation.

Maths

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image