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Question

A function f from the set of natural numbers to integers defined by
f(n)=⎪ ⎪⎪ ⎪n12 if n is oddn12if n is even
is :

A
Onto but not one-one.
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B
One-one and onto both.
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C
Neither one-one nor both.
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D
One-one but not onto.
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Solution

The correct option is A One-one and onto both.
f(n)=⎪ ⎪⎪ ⎪n12if n is odd n2if n is even

f:NI

f(1)=0,f(2)=1,f(3)=1,f(4)=2,f(5)=2,f(6)=3 soon.

If this type of function every element of set A has a unique image in set B and there is no element left in set B. Hence f is one-one and onto function.

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