Question

A function f is defined by $f\left(x\right)=2x^3-3x,xϵR$. What is the value of $f\left(4\right)$?

Answer 1

Given, $f\left(x\right)=2x^3-3x$

To find: $f\left(4\right)$

Therefore, $f\left(4\right)=2{\left(4\right)}^3-3\left(4\right)$

$=2\left(64\right)-12$

$=128-12$

$=116$